Toshiba T2N User Manual download pdf (Page 259)

5. Programming Language

246

PROSEC T2N

(A) B + (B) → (C)

(A) B – (B) → (C)

(A) B ✳ (B) → (C) +1·(C)

(A) B / (B) → (C)

(A) +1·(A) DB + (B) +1·(B) → (C)+1· (C)

(A) +1·(A) DB – (B) +1·(B) → (C)+1· (C)

(A) +1·(A) DB* (B) +1·(B) → (C)+1· (C)

(A) +1·(A) DB / (B) +1·(B) → (C)+1· (C)

(A) B +C (B) →(C)

(A) B – C (B) → (C)

(A) +1· (A) DB +C (B) +1·(B) → (C) +1· (C)

(A) +1· (A) DB – C (B) +1·(B) → (C) +1· (C)

Ladder Diagram Instructions (Function Instructions)

Group

FUN

No.

Name Representation Summary

Number of

steps

required

Execution

time

required

(µs)

Remarks

BCD

operation

192 BCD additon

Carries out BCD addition of the contents of (A) and

(B), and stores the result in (C).

4~6 205

193 BCD subtraction

Subtracts the contents of (B) from the contents of (A)

in BCD, and stores the result in (C).

4~6 197

194 BCD multiplication

Multiplies the contents of (A) and (B) together in

BCD, and stores the result in (C)+1•(C).

4~6 247

195 BCD division

Divides the contents of (A) by the contents of (B) in

BCD, and stores the quotient in (C) and the

remainder in (C)+1.

4~6 250

196

Double-length BCD

addition

Adds the contents of (B)+1 •(B) to the contents of

(A)+1 and (A) in BCD, and stores the result in

(C)+1 •(C).

4~8 372

197

Double-length BCD

subtraction

Subtracts the contents of (B)+1•(B) from the

contents of (A)+1 and (A) in BCD, and stores the

result in (C)+1•(C).

4~8 365

198

Double-length BCD

multiplication

Multiplies the contents of (A)+1•(A) by the contents

of (B)+1•(B) in BCD, and stores the result in (C)+3,

(C)+2, (C)+1•(C).

4~8 672

199

Double-length BCD

division

Divides the contents of (A)+1•(A) by the contents of

(B)+1•(B) in BCD, and stores the quotient in (C)+1

•(C) and the remainder in (C)+3•(C)+2.

4~8 539

200 BCD addition with carry

Adds (B) plus the contents of the carry flag to (A) in

BCD, and stores the result in (C). The carry flag

changes according to the operation result.

4~6 222

201 BCD subtraction with carry

Subtracts (B) plus the contents of the carry flag from

(A) in BCD, and stores the result in (C). The carry

flag changes according to the operation result.

4~6 216

202

Double-length BCD

addition with carry

Adds the contents of (B)+1•(B), plus the contents of

the carry flag, to (A)+1•(A) in BCD, and stores the

result in (C)+1•(C). The carry flag changes

according to the operation result.

4~8 390

203

Double-length BCD

subtraction with carry

Subtracts (B)+1 and (B) plus the contents of the carry

flag from (A)+1•(A) in BCD, and stores the result in

(C)+1•(C). The carry flag changes according to the

operation result.

4~8 383

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